How to sort XML by elements using XSLT?
Create an XML document.
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="books_sorted.xsl"?>
<books>
<book>
<title ISBN="0321173481" author="Michael R. Sweet">
OpenGL Programming Guide Fourth Edition</title>
<publisher>Addison-Wesley</publisher>
<year>2004</year>
</book>
<book>
<title ISBN="0849371643" author="Gerald Farin">
Curves and Surfaces for CAGD: A Practical Guide</title>
<publisher>Academic Press</publisher>
<year>2002</year>
</book>
<book>
<title ISBN="1558606696" author="David Rogers">
An Introduction to NURBS: With Historical Perspective</title>
<publisher>Academic Press</publisher>
<year>2001</year>
</book>
<book>
<title ISBN="1568810849" author="Gerald Farin">
NURBS: From Projective Geometry to Practical Use</title>
<publisher>A K Peters</publisher>
<year>1999</year>
</book>
</books>
Create a XSL stylesheet.
<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" encoding="UTF-8"/>
<xsl:template match="/">
<html>
<head><title>Books</title>
</head>
<body>
<table width="100%" border="1">
<THEAD>
<TR>
<TD width="50%"><B>Publisher</B></TD>
<TD width="50%"><B>Year</B></TD>
</TR>
</THEAD>
<TBODY>
<xsl:for-each select="books/book">
<xsl:sort select="publisher" />
<TR>
<TD width="50%"><xsl:value-of select="publisher" /></TD>
<TD width="50%"><xsl:value-of select="year" /></TD>
</TR>
</xsl:for-each>
</TBODY>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
<xsl:sort> must be placed right after the
<xsl:for-each> or
<xsl:apply-templates> elements.
<xsl:sort select="publisher" /> sorts the selected elements alphabetically. The default sort mode is ascending and the default data-type is text.
When sorting numbers, make sure to set the data-type attribute of
<xsl:sort> to number.
<xsl:sort select="year" data-type="number" order="descending"/> will sort the dates starting from the latest times.
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