It looks like you're new here. If you want to get involved, click one of these buttons!

- 140.9K All Categories
- 103.7K Programming Languages
- 6.5K Assembler Developer
- 1.9K Basic
- 40K C and C++
- 2.9K C#
- 7.9K Delphi and Kylix
- 4 Haskell
- 9.7K Java
- 4.1K Pascal
- 1.3K Perl
- 2K PHP
- 550 Python
- 37 Ruby
- 4.4K VB.NET
- 1.6K VBA
- 20.9K Visual Basic
- 2.6K Game programming
- 317 Console programming
- 92 DirectX Game dev
- 1 Minecraft
- 112 Newbie Game Programmers
- 2 Oculus Rift
- 9K Applications
- 1.8K Computer Graphics
- 742 Computer Hardware
- 3.4K Database & SQL
- 535 Electronics development
- 1.6K Matlab
- 628 Sound & Music
- 258 XML Development
- 3.3K Classifieds
- 199 Co-operative Projects
- 198 For sale
- 190 FreeLance Software City
- 1.9K Jobs Available
- 603 Jobs Wanted
- 209 Wanted
- 2.9K Microsoft .NET
- 1.8K ASP.NET
- 1.1K .NET General
- 3.4K Miscellaneous
- 8 Join the Team
- 355 Comments on this site
- 70 Computer Emulators
- 2.1K General programming
- 187 New programming languages
- 627 Off topic board
- 207 Mobile & Wireless
- 79 Android
- 126 Palm Pilot
- 338 Multimedia
- 154 Demo programming
- 184 MP3 programming
- Bash scripts
- 27 Cloud Computing
- 53 FreeBSD
- 1.7K LINUX programming
- 370 MS-DOS
- Shell scripting
- 321 Windows CE & Pocket PC
- 4.1K Windows programming
- 942 Software Development
- 417 Algorithms
- 68 Object Orientation
- 92 Project Management
- 95 Quality & Testing
- 269 Security
- 7.7K WEB-Development
- 1.8K Active Server Pages
- 62 AJAX
- 4 Bootstrap Themes
- 55 CGI Development
- 28 ColdFusion
- 224 Flash development
- 1.4K HTML & WEB-Design
- 1.4K Internet Development
- 2.2K JavaScript
- 37 JQuery
- 307 WEB Servers
- 150 WEB-Services / SOAP

turbo pascal
Member Posts: **13**

in Matlab

Hi, I have a program that should read a line of text and output the number of words in the line and the number of occurrences of each letter. the output of the letters must be in alphabetical order counting both upper and lowercase versions .(ex input: Hello Hi. And the output: there are 2 words

1 e

2 h

1 i

2 l

1 o

I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

do

{

finish = 0;

for ( i = 0; i < x - 1; i++) // sorting the string..

{

if (s[i] > s[i + 1])

{

hold = s[i];

s[i] = s[i + 1];

s[i + 1] = hold;

finish = 1;

}

}

}while (finish != 0) ;

* so I decided to delete everything that is not a letter but it didn't work…

for (i=0; i<size; i++) // string contains only letters..

if (isalpha(s[i]))

temp[i]=s[i] ;

* and I thought of another way that it didn't work..

for (i=0; i<size; i++) // string contains only letters..

if (!isalpha(s[i]))

s[i]=s[i+1] ;

* finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

for ( i=0;i<x;i++) //counting the occurrences of each letter..

{ for(j=0;j<x;j++)

{

if (s[i]==s[j])

a++ ;

}

cout << s[i] << " occured : " <<a << endl;

a=0;

}

cout << endl;

return 0;

}

1 e

2 h

1 i

2 l

1 o

I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

do

{

finish = 0;

for ( i = 0; i < x - 1; i++) // sorting the string..

{

if (s[i] > s[i + 1])

{

hold = s[i];

s[i] = s[i + 1];

s[i + 1] = hold;

finish = 1;

}

}

}while (finish != 0) ;

* so I decided to delete everything that is not a letter but it didn't work…

for (i=0; i<size; i++) // string contains only letters..

if (isalpha(s[i]))

temp[i]=s[i] ;

* and I thought of another way that it didn't work..

for (i=0; i<size; i++) // string contains only letters..

if (!isalpha(s[i]))

s[i]=s[i+1] ;

* finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

for ( i=0;i<x;i++) //counting the occurrences of each letter..

{ for(j=0;j<x;j++)

{

if (s[i]==s[j])

a++ ;

}

cout << s[i] << " occured : " <<a << endl;

a=0;

}

cout << endl;

return 0;

}

Terms of use / Privacy statement / Publisher: Lars Hagelin

Programmers Heaven articles / Programmers Heaven files / Programmers Heaven uploaded content / Programmers Heaven C Sharp ebook / Operated by CommunityHeaven

© 1997-2015 Programmersheaven.com - All rights reserved.

## Comments

8: Hi, I have a program that should read a line of text and output the number of words in the line and the number of occurrences of each letter. the output of the letters must be in alphabetical order counting both upper and lowercase versions .(ex input: Hello Hi. And the output: there are 2 words

: 1 e

: 2 h

: 1 i

: 2 l

: 1 o

:

: I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

: do

: {

: finish = 0;

: for ( i = 0; i < x - 1; i++) // sorting the string..

: {

: if (s[i] > s[i + 1])

: {

: hold = s[i];

: s[i] = s[i + 1];

: s[i + 1] = hold;

:

: finish = 1;

: }

: }

: }while (finish != 0) ;

:

: * so I decided to delete everything that is not a letter but it didn't work…

:

: for (i=0; i<size; i++) // string contains only letters..

: if (isalpha(s[i]))

: temp[i]=s[i] ;

: * and I thought of another way that it didn't work..

:

: for (i=0; i<size; i++) // string contains only letters..

: if (!isalpha(s[i]))

: s[i]=s[i+1] ;

:

: * finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

:

: for ( i=0;i<x;i++) //counting the occurrences of each letter..

: { for(j=0;j<x;j++)

: {

: if (s[i]==s[j])

: a++ ;

: }

: cout << s[i] << " occured : " <<a << endl;

: a=0;

: }

: cout << endl;

: return 0;

: }

:

:

:

:

:

:

: