It looks like you're new here. If you want to get involved, click one of these buttons!

- 141.2K All Categories
- 103.9K Programming Languages
- 6.5K Assembler Developer
- 1.9K Basic
- 40K C and C++
- 2.9K C#
- 7.9K Delphi and Kylix
- 4 Haskell
- 9.7K Java
- 4.1K Pascal
- 1.3K Perl
- 2K PHP
- 553 Python
- 37 Ruby
- 4.4K VB.NET
- 1.6K VBA
- 20.9K Visual Basic
- 2.6K Game programming
- 317 Console programming
- 93 DirectX Game dev
- 1 Minecraft
- 112 Newbie Game Programmers
- 2 Oculus Rift
- 9K Applications
- 1.8K Computer Graphics
- 748 Computer Hardware
- 3.5K Database & SQL
- 535 Electronics development
- 1.6K Matlab
- 628 Sound & Music
- 258 XML Development
- 3.3K Classifieds
- 199 Co-operative Projects
- 199 For sale
- 190 FreeLance Software City
- 1.9K Jobs Available
- 605 Jobs Wanted
- 213 Wanted
- 2.9K Microsoft .NET
- 1.8K ASP.NET
- 1.1K .NET General
- 3.4K Miscellaneous
- 7 Join the Team
- 356 Comments on this site
- 71 Computer Emulators
- 2.1K General programming
- 188 New programming languages
- 641 Off topic board
- 226 Mobile & Wireless
- 98 Android
- 126 Palm Pilot
- 340 Multimedia
- 156 Demo programming
- 184 MP3 programming
- Bash scripts
- 28 Cloud Computing
- 53 FreeBSD
- 1.7K LINUX programming
- 371 MS-DOS
- Shell scripting
- 321 Windows CE & Pocket PC
- 4.1K Windows programming
- 944 Software Development
- 417 Algorithms
- 68 Object Orientation
- 92 Project Management
- 95 Quality & Testing
- 271 Security
- 7.7K WEB-Development
- 1.8K Active Server Pages
- 62 AJAX
- 6 Bootstrap Themes
- 55 CGI Development
- 28 ColdFusion
- 224 Flash development
- 1.4K HTML & WEB-Design
- 1.4K Internet Development
- 2.2K JavaScript
- 37 JQuery
- 310 WEB Servers
- 157 WEB-Services / SOAP

turbo pascal
Member Posts: **13**

in Matlab

Hi, I have a program that should read a line of text and output the number of words in the line and the number of occurrences of each letter. the output of the letters must be in alphabetical order counting both upper and lowercase versions .(ex input: Hello Hi. And the output: there are 2 words

1 e

2 h

1 i

2 l

1 o

I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

do

{

finish = 0;

for ( i = 0; i < x - 1; i++) // sorting the string..

{

if (s[i] > s[i + 1])

{

hold = s[i];

s[i] = s[i + 1];

s[i + 1] = hold;

finish = 1;

}

}

}while (finish != 0) ;

* so I decided to delete everything that is not a letter but it didn't work…

for (i=0; i<size; i++) // string contains only letters..

if (isalpha(s[i]))

temp[i]=s[i] ;

* and I thought of another way that it didn't work..

for (i=0; i<size; i++) // string contains only letters..

if (!isalpha(s[i]))

s[i]=s[i+1] ;

* finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

for ( i=0;i<x;i++) //counting the occurrences of each letter..

{ for(j=0;j<x;j++)

{

if (s[i]==s[j])

a++ ;

}

cout << s[i] << " occured : " <<a << endl;

a=0;

}

cout << endl;

return 0;

}

1 e

2 h

1 i

2 l

1 o

I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

do

{

finish = 0;

for ( i = 0; i < x - 1; i++) // sorting the string..

{

if (s[i] > s[i + 1])

{

hold = s[i];

s[i] = s[i + 1];

s[i + 1] = hold;

finish = 1;

}

}

}while (finish != 0) ;

* so I decided to delete everything that is not a letter but it didn't work…

for (i=0; i<size; i++) // string contains only letters..

if (isalpha(s[i]))

temp[i]=s[i] ;

* and I thought of another way that it didn't work..

for (i=0; i<size; i++) // string contains only letters..

if (!isalpha(s[i]))

s[i]=s[i+1] ;

* finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

for ( i=0;i<x;i++) //counting the occurrences of each letter..

{ for(j=0;j<x;j++)

{

if (s[i]==s[j])

a++ ;

}

cout << s[i] << " occured : " <<a << endl;

a=0;

}

cout << endl;

return 0;

}

Terms of use / Privacy statement / Publisher: Lars Hagelin

Programmers Heaven articles / Programmers Heaven files / Programmers Heaven uploaded content / Programmers Heaven C Sharp ebook / Operated by CommunityHeaven

© 1997-2017 Programmersheaven.com - All rights reserved.

## Comments

8: Hi, I have a program that should read a line of text and output the number of words in the line and the number of occurrences of each letter. the output of the letters must be in alphabetical order counting both upper and lowercase versions .(ex input: Hello Hi. And the output: there are 2 words

: 1 e

: 2 h

: 1 i

: 2 l

: 1 o

:

: I've done the first part but I couldn't solve the second part. first, I changed all the uppercase to lowercase.then,I found this sort but I have the spaces and other punctuations showing with it..

: do

: {

: finish = 0;

: for ( i = 0; i < x - 1; i++) // sorting the string..

: {

: if (s[i] > s[i + 1])

: {

: hold = s[i];

: s[i] = s[i + 1];

: s[i + 1] = hold;

:

: finish = 1;

: }

: }

: }while (finish != 0) ;

:

: * so I decided to delete everything that is not a letter but it didn't work…

:

: for (i=0; i<size; i++) // string contains only letters..

: if (isalpha(s[i]))

: temp[i]=s[i] ;

: * and I thought of another way that it didn't work..

:

: for (i=0; i<size; i++) // string contains only letters..

: if (!isalpha(s[i]))

: s[i]=s[i+1] ;

:

: * finally I decided to do the counting any way, but I have the occurrences of each letter repeated as many times as it occurred, as well as ,counting punctuations.

:

: for ( i=0;i<x;i++) //counting the occurrences of each letter..

: { for(j=0;j<x;j++)

: {

: if (s[i]==s[j])

: a++ ;

: }

: cout << s[i] << " occured : " <<a << endl;

: a=0;

: }

: cout << endl;

: return 0;

: }

:

:

:

:

:

:

: