I am looking for a c program which will do the following task

1. accept 2 integers say a , b

2. perform the division

if a = 1 and b = 7

then a/b = 0.33333333333333333333333333333333

3. output shoud be 0.(3)

or if answer is 0.111221111122111112211

then it should display 0.(1112211)

or if it is 0.142857142857142857142857

then 0.(142857)

etc...

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## Comments

:

: I am looking for a c program which will do the following task

:

: 1. accept 2 integers say a , b

: 2. perform the division

: if a = 1 and b = 7

: then a/b = 0.33333333333333333333333333333333

: 3. output shoud be 0.(3)

:

: or if answer is 0.111221111122111112211

: then it should display 0.(1112211)

:

: or if it is 0.142857142857142857142857

: then 0.(142857)

:

: etc...

:

:

:

The only safe way I can think of is to do the division yourself:

[code]

7/1.0.142857

7

---

30

28

--

20

14

--

60

56

--

40

35

--

50

49

--

1 <---- Same number we started with, so repetition from here.

[/code]

Greets,

Eric Goldstein

www.gvh-maatwerk.nl

:

:

:

That was my first thought too, but that's not safe.

One could have a number that seems to repeat, but stops repeating beyond the accuracy of the float or double.

And how about 1/6 = 0.1(6)?

Greets,

Eric Goldstein

www.gvh-maatwerk.nl

: :

: :

: :

: That was my first thought too, but that's not safe.

: One could have a number that seems to repeat, but stops repeating beyond the accuracy of the float or double.

: And how about 1/6 = 0.1(6)?

:

:

: Greets,

: Eric Goldstein

: www.gvh-maatwerk.nl

:

:

I like your idea, Eric, but it could be improved.

If we get to a number we where at before.

This is written from head with no knowledge of string funcs in C++...

[code]

int a = 1, b=6;

int* array = new int[100];

string s = "";

for(int i = 0; i < 100; ++i){

s += a / b;

a = a % b;

if(array[a] == 0)

array[a] = i;

else{ //found a match

//don't want to write this right now: :-)

s = s[0 to array[a]] + '(' + s[array[a] + 1 to end] + ')';

break;

}

}

[/code]

I think the array could be minimized to the size of b...

I also think I've done something wrong. The dot wont work with this...

Happy coding wishes

the one and only

[b]Niklas Ulvinge[/b] [white]aka [b]IDK[/b][/white]

: That was my first thought too, but that's not safe.

: One could have a number that seems to repeat, but stops repeating beyond the accuracy of the float or double.

: And how about 1/6 = 0.1(6)?

:

:

1/6 does not stop repeating. But I understand what you are saying. How far do you need to carry out the division before you give up and say that the sequence repeats forever? [b]Infinite[/b] is not an acceptable answer because the problem would never be solved.

: : That was my first thought too, but that's not safe.

: : One could have a number that seems to repeat, but stops repeating beyond the accuracy of the float or double.

: : And how about 1/6 = 0.1(6)?

: :

: :

:

: 1/6 does not stop repeating. But I understand what you are saying. How far do you need to carry out the division before you give up and say that the sequence repeats forever? [b]Infinite[/b] is not an acceptable answer because the problem would never be solved.

:

:

You're right about that. In that case, maybe you should combine both methods:

String-search for a repeating pattern to suspect a repetition and try to prove it by hand-division.

Greets,

Eric Goldstein

www.gvh-maatwerk.nl

: : That was my first thought too, but that's not safe.

: : One could have a number that seems to repeat, but stops repeating beyond the accuracy of the float or double.

: : And how about 1/6 = 0.1(6)?

: :

: :

:

: 1/6 does not stop repeating. But I understand what you are saying. How far do you need to carry out the division before you give up and say that the sequence repeats forever? [b]Infinite[/b] is not an acceptable answer because the problem would never be solved.

:

:

....... the size is not a problem it is expected that it should work for size n... i mean if u declear size of the string 100 then it will consider only first 100 digits from fractional part... and so on

: :

: : I am looking for a c program which will do the following task

: :

: : 1. accept 2 integers say a , b

: : 2. perform the division

: : if a = 1 and b = 7

: : then a/b = 0.33333333333333333333333333333333

: : 3. output shoud be 0.(3)

: :

: : or if answer is 0.111221111122111112211

: : then it should display 0.(1112211)

: :

: : or if it is 0.142857142857142857142857

: : then 0.(142857)

: :

: : etc...

: :

: :

: :

:

: The only safe way I can think of is to do the division yourself:

: [code]

: 7/1.0.142857

: 7

: ---

: 30

: 28

: --

: 20

: 14

: --

: 60

: 56

: --

: 40

: 35

: --

: 50

: 49

: --

: 1 <---- Same number we started with, so repetition from here.

: [/code]

:

: Greets,

: Eric Goldstein

: www.gvh-maatwerk.nl

:

:

............... it will not work for many cases like

a = 11 and b = 59

then output is

0.(1864406779661016949152542372881355932203389830508474576271)

so at 2nd '1' we can not stop....

: : : That was my first thought too, but that's not safe.

: : : One could have a number that seems to repeat, but stops repeating beyond the accuracy of the float or double.

: : : And how about 1/6 = 0.1(6)?

: : :

: : :

: :

: : 1/6 does not stop repeating. But I understand what you are saying. How far do you need to carry out the division before you give up and say that the sequence repeats forever? [b]Infinite[/b] is not an acceptable answer because the problem would never be solved.

: :

: :

: ....... the size is not a problem it is expected that it should work for size n... i mean if u declear size of the string 100 then it will consider only first 100 digits from fractional part... and so on

:

If you looked at my wrong code, and maybe my wrong statement, I think it could only repeat for max the denominator.