Maximum value in results - Programmers Heaven

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# Maximum value in results

Posts: 2Member
Hi, I'm looking for with some pascal code. I have to make a program which allows you to input a name and an amount four times. Then it is supposed to output the name, three percentages of the amount and the maximum of one of the percentage out of the four outputted results. can any one help? This is what I have so far:

program grocery;
uses wincrt;
var
Name:Array[1..4] of String;
Amount:Array[1..4] of longint;
i:Integer;
B_sector,L_sector,V_sector:double;
Begin
For i:=1 to 4 do
Begin;
Writeln('Enter Organisation Name');
Writeln('Enter the amount');
B_sector:=(Amount[i])*40/100;
V_sector:=(Amount[i])*25/100 ;
L_sector:=(Amount[i])*35/100 ;
Writeln(Name[i]);
Writeln(B_sector:2:1);
Writeln(V_sector:2:1);
Writeln(L_sector:2:1);

End;

End.

• Posts: 24Member
not sure about the maximum you want but have a look at this:

program grocery;
uses wincrt;
var
Name:Array[1..4] of String;
Amount:Array[1..4] of longint;
i,j:Integer;
B_sector,L_sector,V_sector:double;

sector:array[1..4,1..3] of double;
max: double;
begin

for i:=1 to 4 do
begin;
Writeln('Enter Organisation Name');

Writeln('Enter the amount');

{B_sector:=(Amount[i])*40/100;
V_sector:=(Amount[i])*25/100 ;
L_sector:=(Amount[i])*35/100 ;}

sector[i,1]:=(Amount[i])*40/100;
sector[i,2]:=(Amount[i])*25/100;
sector[i,3]:=(Amount[i])*35/100;

Writeln(Name[i]);
Write(sector[i,1]:0:5,' ');
Write(sector[i,2]:0:5,' ');
Writeln(sector[i,3]:0:5);
end;

max:=sector[1,1];
for i:=1 to 4 do
for j:=1 to 3 do if sector[i,j]>=max then max:=sector[i,j];

writeln(max:0:5);

end.
• Posts: 24Member
or better this:

program grocery;
uses wincrt;
var
Name:Array[1..3] of String;
Amount:Array[1..3] of longint;
i,j:Integer;
B_sector,L_sector,V_sector:double;

sector:array[1..3,1..3] of double;
max: double;
begin

for i:=1 to 3 do
begin
Writeln('Enter Organisation Name');

Writeln('Enter the amount');
end;

clrscr;

for i:=1 to 3 do
begin

{B_sector:=(Amount[i])*40/100;
V_sector:=(Amount[i])*25/100 ;
L_sector:=(Amount[i])*35/100 ;}

sector[i,1]:=(Amount[i])*40/100;
sector[i,2]:=(Amount[i])*25/100;
sector[i,3]:=(Amount[i])*35/100;

Writeln(Name[i],':');
Write(sector[i,1]:0:5,' ');
Write(sector[i,2]:0:5,' ');
Writeln(sector[i,3]:0:5);
writeln;
end;

max:=sector[1,1];
for i:=1 to 3 do
for j:=1 to 3 do if sector[i,j]>=max then max:=sector[i,j];

writeln;
write('the max percentage is: ',max:0:5);

end.
• Posts: 1Member
The site wont let me use my profile, so i had to make this new one. But thanks anyway