Howdy, Stranger!

It looks like you're new here. If you want to get involved, click one of these buttons!

Categories

how to replace too many if statements

Gloria99Gloria99 Posts: 2Member
Hi all,

Iam building a code in bioinformatics field.. I have 2 matrix comeing from a certain code as follows:

[code]
m1 =
'GO:0008150' 'GO:0016740'
'GO:0016740' 'GO:0016787'
'GO:0016787' 'GO:0006810'
'GO:0008150' 'GO:0006412'
'GO:0016740' 'GO:0004672'
'GO:0016740' 'GO:0016779'
'GO:0016787' 'GO:0004386'
'GO:0016787' 'GO:0003774'
'GO:0016787' 'GO:0016298'
'GO:0006810' 'GO:0016192'

m2 =
'GO:0008150' 'GO:0016787'
'GO:0008150' 'GO:0006810'
'GO:0006810' 'GO:0006412'
'GO:0016192' 'GO:0003774'
'GO:0006810' 'GO:0005215'
'GO:0005215' 'GO:0030533'[/code]

in each matrix, the first column is the parent of the second one... I need from the code to find the part of graph which can determine all relations between these cells... I have to find cell from column 1 that occurance in column 2, then take the cell from column 1 but from the same row of column 2 and find the similarity between it and onother cell in column 2 .. and so.. it is something like depth first search in graph theory

In general, How can I make a dynamic code (recursive) that can replace the following if statements:
[code]
for k=1:length(m1)
for ii=1:length(m1)
for j=1:length(m1)
for i=1:length(m2)
for e=1:length(m1)
if isequal(m2{i,1},m1{j,2})
x1=[m1(j,1) m2(i,2)];
x11=[x1;x11];
if isequal(m1{j,1},m1{k,2})
x2=[m1(k,1),m2(i,2)];
x22=[x2;x22];
if isequal(m1{k,1},m1{ii,2})
x3=[m1(ii,1),m2(i,2)];
x33=[x3;x33];
if isequal(m1{ii,1},m1{e,2})
x4=[m1(e,1),m2(i,2)];
x44=[x4;x44];
.
.
and so..x_total=[x11;x22;x33;x44...]
end
end
end
end
end
end
end[/code]

Note that the if statemtnes are not determined( it depends on m1 & m2 which are also not always constants)


Sign In or Register to comment.