hi everyone,
i would be really greatefull if anybody can solve these 3 pproblems of mine :
1. I want to make a type in pascal whose size should be only 2 bits, so that there will be only 4 possible values for it(00,01,10,11).
2. Next i want to make an array of this type.
3. The important thing is i want to set the size of the array at runtime.
waiting eagerly for replies..thanking in anticipation
Comments
: hi everyone,
:
: i would be really greatefull if anybody can solve these 3 pproblems of mine :
:
: 1. I want to make a type in pascal whose size should be only 2 bits, so that there will be only 4 possible values for it(00,01,10,11).
:
: 2. Next i want to make an array of this type.
:
: 3. The important thing is i want to set the size of the array at runtime.
:
: waiting eagerly for replies..thanking in anticipation
:
1) Well probably you can't make a type which consists of 2 bits only. Here is another solution:
[code]
type
My2bit = (b00,b01,b10,b11);
[/code]
2) Simple:
[code]
var
bitarray=array[1..40] of my2bit; { 1 and 40 can be any other value }
[/code]
3) Well, at runtime - this is not possible I'm afraid. But, maybe I miunderstood your question, maybe this is what you're looking for:
[code]
var
x:byte;
bitarray:array[1..x] of my2bit;
[/code]
Hope this help you out. And, sorry for my english.
****************
Any questions? Just ask!
:-) [b][blue]GAASHIUS[/blue][/b] :-)
: : hi everyone,
: :
: : i would be really greatefull if anybody can solve these 3 pproblems of mine :
: :
: : 1. I want to make a type in pascal whose size should be only 2 bits, so that there will be only 4 possible values for it(00,01,10,11).
: :
: : 2. Next i want to make an array of this type.
: :
: : 3. The important thing is i want to set the size of the array at runtime.
: :
: : waiting eagerly for replies..thanking in anticipation
: :
: 1) Well probably you can't make a type which consists of 2 bits only. Here is another solution:
: [code]
: type
: My2bit = (b00,b01,b10,b11);
: [/code]
:
: 2) Simple:
: [code]
: var
: bitarray=array[1..40] of my2bit; { 1 and 40 can be any other value }
: [/code]
:
: 3) Well, at runtime - this is not possible I'm afraid. But, maybe I miunderstood your question, maybe this is what you're looking for:
: [code]
: var
: x:byte;
: bitarray:array[1..x] of my2bit;
: [/code]
:
: Hope this help you out. And, sorry for my english.
:
: ****************
: Any questions? Just ask!
:
: :-) [b][blue]GAASHIUS[/blue][/b] :-)
:
:
:
The only 2 ways of creating dynamically memory lists are:
- TMemoryStream (or a descendant of it)
- linked-list
A linked list uses records, where each record consists of at least 2 fields: 1 or more for the data, and 1 for the location of the next record. In your case that would be:
[code]
type
PMy2Bits = ^TMy2Bits;
TMy2Bits = record
Bits: My2bit;
Next: PMy2Bits;
end;
[/code]
This way you can link records together, by only remembering the location of the first record:
[code]
var
MyBitsArray: PMy2Bits;
[/code]
The drawback of this way is that the coding of the navigation quite involved is. For example: to get the indexth 2-bits you need something like this:
[code]
function GetBits(index: integer): My2bit;
var
i: integer;
begin
Current := MyBitsArray;
i := 0;
while i < Index do
begin
Current := Current^.Next;
inc(i);
end;
Result := Current^.Bits;
end;
[/code]
Also each record must be specifically be created using the New() statement.
i checked it on boolean and i think i taken 1 byte for a every part of the array.
check this out
array[1..x]of boolean
you can check their size using sizeof function.
type
My2bit = (b00,b01);
bitarray=array[1..40] of my2bit;
boolarray=array[1..40]of boolean;
begin
writeln(sizeof(bitarray));
writeln(sizeof(boolarray));
{hopefully each 1 will take 5 bytes and not 40...}
good luck
dolev
: i checked it on boolean and i think i taken 1 byte for a every part of the array.
: check this out
: array[1..x]of boolean
:
:
: you can check their size using sizeof function.
:
: type
: My2bit = (b00,b01);
: bitarray=array[1..40] of my2bit;
: boolarray=array[1..40]of boolean;
:
: begin
: writeln(sizeof(bitarray));
: writeln(sizeof(boolarray));
:
: {hopefully each 1 will take 5 bytes and not 40...}
:
: good luck
: dolev
:
:
Each array will take 40 bytes, because the smallest memory unit pascal can handle is the byte. If you truely want to have just 2 bits, then you need to cast the array like this:
[code]
My2Bits: array[1..10] of byte;
[/code]
and use the various bitwise logical operators to get the bits. For example the following code will get the first 2 bits of the first element:
[code]
First2Bits := My2Bits[1] and $03;
[/code]
[code]
TYPE
MyBits = record
Bits : Array[0..9] Of Byte;
Next : Pointer;
End;
MyBitsPtr = ^MyBits;
VAR
Start : Pointer;
Current : Pointer;
Last : Pointer;
PROCEDURE GetNewRecord;
VAR
NewRec : Pointer;
Begin
NewRec := New(MyBitsPtr);
If Start = nil then
Begin
Start := NewRec;
Current := Start;
Last := Start;
End
ELSE
Begin
Last^.Next := NewRec
Last := Last^.Next;
End;
Last^.Next := Nil;
End;
PROCEDURE DisposeRecords;
Begin
Current := Start;
While Current^.Next <> Nil Do
Begin
Current := Current^.Next;
Dispose(Start);
Start := Current;
End;
If Start <> nil Then Dispose(Start);
Start := nil;
Current := nil;
Last := nil;
End;
FUNCTION Get2Bit(Num : Word);
Begin
{Blah blah blah}
End;
FUNCTION GetNext2Bit;
Begin
{Blah blah blah}
End;
FUNCTION SetNext2Bit(Bits : Byte); { Or SetNext2bit(Bit1,Bit2 : Boolean);
Begin
{Blah blah blah}
End;
Begin
GetNewRecord;
DisposeRecords;
End.
[/code]
This would allow eighty 2-bits variables for each record and also allow for expansion at the cost of only 14 bytes of memory for each.
You could also expanded this to hold more in one record since the pointer is currently taking up almost 1/3 of the allocated memory.
Phat Nat
: hi everyone,
:
: i would be really greatefull if anybody can solve these 3 pproblems of mine :
:
: 1. I want to make a type in pascal whose size should be only 2 bits, so that there will be only 4 possible values for it(00,01,10,11).
:
: 2. Next i want to make an array of this type.
:
: 3. The important thing is i want to set the size of the array at runtime.
:
: waiting eagerly for replies..thanking in anticipation
:
you can't use only 2 bits, however if you use 2 bits you can pack 4 of those values into one byte
the bytes needed for n values of size 2 bits is n*2/8 rounded towards positive infinity (aka Ceil()) or this code:
[code]
size := (n*2) div 8;
if n mod 4 <> 0 then size := size + 1; {not full filling of bytes}
[/code]
and to access the m'th byte you need
[code]
ofs := m mod 4;
val := arr^[m div 4] shr ofs; {i'll explain arr^ later}
arr^[m div 4] := (arr^[m div 4] and (not (3 shl ofs))) or (val shl ofs);
{3 shr ofs will move 11B to the right place. not will make it into 11001111B etc. "and" will remove old data at that place and "or" will add new data}
[/code]
ofs is the local offset in the byte. Note: i write this as it comes up in my mind, might be typos or calculating errors
to create dynamic array:
[code]
type
parr = ^tarr
tarr = array[0..0] of byte;
...
var
n: integer;
arr: parr;
...
n := 10; //we want to store 10 values
size := (n*2) div 8;
if n mod 4 <> 0 then size := size + 1; {not full filling of bytes}
getmem(arr, size);
fillchhar(arr^, size, 0);
...
{and don't forget:} freemem(arr, size);
[/code]
arr will be a pointer to an array[0..0]. this might seem odd but if you turn of run-time range checking, you can access any element, even larger than 0 making this a dynamic array. note that you need to use variable indexes (not constants!) or borland's pascal compiler will die with an out-of-range compile-error if you use other than 0 for the index
once you get the value
[hr][red][italic][b]N[/b][/red][blue]et[/blue][red][b]G[/b][/red][blue]ert[/italic][/blue][hr]
: : i checked it on boolean and i think i taken 1 byte for a every part of the array.
: : check this out
: : array[1..x]of boolean
: :
: :
: : you can check their size using sizeof function.
: :
: : type
: : My2bit = (b00,b01);
: : bitarray=array[1..40] of my2bit;
: : boolarray=array[1..40]of boolean;
: :
: : begin
: : writeln(sizeof(bitarray));
: : writeln(sizeof(boolarray));
: :
: : {hopefully each 1 will take 5 bytes and not 40...}
: :
: : good luck
: : dolev
: :
: :
: Each array will take 40 bytes, because the smallest memory unit pascal can handle is the byte. If you truely want to have just 2 bits, then you need to cast the array like this:
: [code]
: My2Bits: array[1..10] of byte;
: [/code]
: and use the various bitwise logical operators to get the bits. For example the following code will get the first 2 bits of the first element:
: [code]
: First2Bits := My2Bits[1] and $03;
: [/code]
:
This is true of Borland variants, but is this a Borland Only message board?
The following results in usage of only two bits on my compiler for each element (UCSD IV.0). Your mileage may vary. You need to consult your compiler docs or use sizeof to determine the usage:
[code]
Var My2Bits: packed array[0..1] of 0..3;
[/code]
My2Bits occupies only one 16-bit word of memory, and 12 of the bits in that word are unused.
Ben
: This is true of Borland variants, but is this a Borland Only message board?
[blue]Borland's compiler is the default and usually preferred one. however, nowadays freepascal is taking over. you can't assume someone is using XYZ compiler, however it is safe to assume BPC to be used as all pascal compilers need to support what it does[/blue]
:
: The following results in usage of only two bits on my compiler for each element (UCSD IV.0). Your mileage may vary. You need to consult your compiler docs or use sizeof to determine the usage:
:
: [code]
:
: Var My2Bits: packed array[0..1] of 0..3;
:
: [/code]
:
: My2Bits occupies only one 16-bit word of memory, and 12 of the bits in that word are unused.
:
: Ben
:
[hr][red][italic][b]N[/b][/red][blue]et[/blue][red][b]G[/b][/red][blue]ert[/italic][/blue][hr]