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Is there a way to do this?

RiddickRiddick
in C#
Suppose we have an interface I with one method, call it method(). We have class A that implements the interface, and a class B that derive from A. Both classes decide to hidde the implementation of the interface. How can a method of class B, lets call it ShowUpperMethod(), can call method() in A

PD> Here is the code to help understand... :) thx.

namespace ExplicitImplementation
{
public interface I
{
void method ();
}

public class A : I
{
void I.method ()
{
Console.WriteLine ("Im class A implementing interface...");
}
}

public class B : A, I
{
public void ShowUpperMethod ()
{
// I want to call the method() in the upper class.
}

void I.method ()
{
Console.WriteLine ("Im class B implementing interface...");
}
}
}

Comments

  • SoEnLionSoEnLion
    This code may help you. To call an upper method you can use the key word "base".


    namespace ConsoleApplication1
    {
    class Program
    {

    public static void Main(string[] args)
    {
    A expA = new A();
    B expB = new B();

    expA.method();
    expB.ShowUpperMethod();
    expB.method();
    Console.ReadKey();

    }
    }

    public interface I
    {
    void method();
    }

    public class A : I
    {
    public void method()
    {
    Console.WriteLine("Im class A implementing interface...");
    }
    }

    public class B : A, I
    {
    public void ShowUpperMethod()
    {
    base.method();
    }

    public void method()
    {
    Console.WriteLine("Im class B implementing interface...");
    }
    }
    }
  • SoEnLionSoEnLion
    This post has been deleted.
  • RiddickRiddick
    Ok, I understand that part. However, I wanted the methods to be hiden in both clases. Like I showed before:

    void I.method ()

    See the example that I had there.

    Any clue? I mean I haven't figure out.
  • RiddickRiddick
    This post has been deleted.
  • RiddickRiddick
    This post has been deleted.
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