I'm looking to right to a specific address. This will explain...

#include <iostream.h>

int main()
{
    int a = 0;

    cout<< &a;

    // let's say the address of 'a' is 0x265dda4.
    // How would I write to the address of 0x265dda4?

    // 0x265dda4 = 12;            ?
}

It doesn't really HAVE to be the address 0x265dda4. It could be anything. My point is, is there any way that C++ can write to a specific address? Arigato.

: It doesn't really HAVE to be the address 0x265dda4. It could be anything. My point is, is there any way that C++ can write to a specific address? Arigato.
:
:

Can't do it with any 32-bit compiler in either *nix or MS Windows. Don't know about MAC (but I suspect that would be forbidden as well). You can do it with 16-bit MS-DOS compiler such as Turbo C but you have to use the segment:offset notation, such as 0004:0020 (one of the interrupt tables).

: I'm looking to right to a specific address. This will explain...
:
:

: #include <iostream.h>
: 
: int main()
: {
:     int a = 0;
: 
:     cout<< &a;
: 
:     // let's say the address of 'a' is 0x265dda4.
:     // How would I write to the address of 0x265dda4?
: 
:     // 0x265dda4 = 12;            ?
: }
: 

:
: It doesn't really HAVE to be the address 0x265dda4. It could be anything. My point is, is there any way that C++ can write to a specific address? Arigato.
:
:

You can access only your address space in protected mode (as in Win32 or Unix), you cannot use far pointers. So you can do this:

int *a;

a = (int *)0x0265dda4;
*a = 10;

--
Long live Rock & Roll!

Psycho Clown.