#include <stdio.h>
#include <math.h>

void main()
{
int i = 25, j = 2, k = 5;
printf("%.2f\n", sqrt(i));
printf("%.2f\n", pow(j,k));

}



it aint working for me

Well, if you change the code around a bit:
#include <stdio.h>
#include <math.h>

int main() /* If you compiled with a C++ compiler you must change main()'s return type to 'int'. */
{
int i = 25, j = 2, k = 5;
printf("%.2f\n", sqrt(i));
printf("%.2f\n", pow(j,k));

/* Get some input, so the program stays running long enough to read the output. */
int extra;
scanf("32%s", extra);
}

...You get this for output:
5.00
32.00

how?

: how?
:
you been watching some old John Wayne westerns? How what???

: #include <stdio.h>
: #include <math.h>
:
: void main()
: {
: int i = 25, j = 2, k = 5;
: printf("%.2f\n", sqrt(i));
: printf("%.2f\n", pow(j,k));
:
: }
:
:
:
: it aint working for me

the code is clearly fine and obviously produce some valid output as i expected. why dont u check with a compiler rather than asking us? what is ur expectation from the code? be more specific.