include <stdio.h>

void xxx( int*, int);
void main()
{
int x =4, y = 13;
xxx(&x, y);
printf("%d%d\n", x, y);
}

void xxx(int* x, int y)
{
*x += 4;
y += 7;
printf("%d%d\n", *x, y);
}


820
813

I cant understand why-

This message was edited by stober at 2005-8-8 16:48:40

---

: include <stdio.h>
:
: void xxx( int*, int);
: void main()
: {
: int x =4, y = 13;
: xxx(&x, y);
: printf("%d%d\n", x, y);
: }
:
: void xxx(int* x, int y)
: {
: *x += 4;
: y += 7;
: printf("%d%d\n", *x, y);
: }
:
:
: 820
: 813
:
: I cant understand why-
:

you need to separate the numbers with one or more spaces -- they are all run togethere.

:   printf("%d  %d\n", *x, y);

Look at your format specifiers in the printf statements

%d%d will make two numbers appear as one, or if you don't know where the 8 came from, then read up on pointers a bit more.

: include <stdio.h>
:
: void xxx( int*, int);
: void main()
: {
: int x =4, y = 13;
: xxx(&x, y);
: printf("%d%d\n", x, y);
: }
:
: void xxx(int* x, int y)
: {
: *x += 4;
: y += 7;
: printf("%d%d\n", *x, y);
: }
:
:
: 820
: 813
:
: I cant understand why-
: