In the getline function you have to specify how many characters you want to extract. istream& getline (char* s, streamsize n, char delim );

To me that is dumb, becuase it is not going to actually get the line if it is larger than you expected. Is there a way to get the whole line no matter how large it is?

This message was edited by jambeard at 2006-4-2 14:28:9

---

: In the getline function you have to specify how many characters you want to extract. istream& getline (char* s, streamsize n, char delim );
:
: To me that is dumb, becuase it is not going to actually get the line if it is larger than you expected. Is there a way to get the whole line no matter how large it is?
:


If I were you I'd sack off trying to use that, I found using the getline function loads of hassle!!

Try this:

string readLine(istream &in, string &s)
{
	string returnString;

	char c;

	s.erase();	// clear the old string

	c = in.get();		// read one character ahead
	while ( c!='\n' )
	{
		s = s + c;		// add the string
		c = in.get();	// read the next character
	}

	returnString = s;

	return returnString;
}

And use it like this:

int main()
{
    string lineOfText;    //Place to store the line of text

    readLine(cin, lineOfText);    //read the line

    cout << "You wrote " << lineOfText << endl;    //Output what the user entered

    return 0;
}

Hope it helps.

J

: This message was edited by jambeard at 2006-4-2 14:28:9

---

: : In the getline function you have to specify how many characters you want to extract. istream& getline (char* s, streamsize n, char delim );
: :
: : To me that is dumb, becuase it is not going to actually get the line if it is larger than you expected. Is there a way to get the whole line no matter how large it is?
: :
:
:
: If I were you I'd sack off trying to use that, I found using the getline function loads of hassle!!
:
: Try this:
:
:

: string readLine(istream &in, string &s)
: {
: 	string returnString;
: 
: 	char c;
: 
: 	s.erase();	// clear the old string
: 
: 	c = in.get();		// read one character ahead
: 	while ( c!='\n' )
: 	{
: 		s = s + c;		// add the string
: 		c = in.get();	// read the next character
: 	}
: 
: 	returnString = s;
: 
: 	return returnString;
: }
: 

:
: And use it like this:
:
:

: int main()
: {
:     string lineOfText;    //Place to store the line of text
: 
:     readLine(cin, lineOfText);    //read the line
: 
:     cout << "You wrote " << lineOfText << endl;    //Output what the user entered
: 
:     return 0;
: }
: 

:
: Hope it helps.
:
: J
:
:
:


And for C, replace cin.get() with fgets().

: : This message was edited by jambeard at 2006-4-2 14:28:9

---

: : : In the getline function you have to specify how many characters you want to extract. istream& getline (char* s, streamsize n, char delim );
: : :
: : : To me that is dumb, becuase it is not going to actually get the line if it is larger than you expected. Is there a way to get the whole line no matter how large it is?
: : :
: :
: :
: : If I were you I'd sack off trying to use that, I found using the getline function loads of hassle!!
: :
: : Try this:
: :
: :

: : string readLine(istream &in, string &s)
: : {
: : 	string returnString;
: : 
: : 	char c;
: : 
: : 	s.erase();	// clear the old string
: : 
: : 	c = in.get();		// read one character ahead
: : 	while ( c!='\n' )
: : 	{
: : 		s = s + c;		// add the string
: : 		c = in.get();	// read the next character
: : 	}
: : 
: : 	returnString = s;
: : 
: : 	return returnString;
: : }
: : 

: :
: : And use it like this:
: :
: :

: : int main()
: : {
: :     string lineOfText;    //Place to store the line of text
: : 
: :     readLine(cin, lineOfText);    //read the line
: : 
: :     cout << "You wrote " << lineOfText << endl;    //Output what the user entered
: : 
: :     return 0;
: : }
: : 

: :
: : Hope it helps.
: :
: : J
: :
: :
: :
:
:
: And for C, replace cin.get() with fgets().
:
Or you could just use..

#include <string>
#include <iostream>
using namespace std;

int main(int argc, char* argv[])
{
	string input;
	cout << "Enter a string: ";
	getline( cin, input );
	cout << "The string is: " << input << endl;
	return 0;
}

: Or you could just use..
:

: #include <string>
: #include <iostream>
: using namespace std;
: 
: int main(int argc, char* argv[])
: {
: 	string input;
: 	cout << "Enter a string: ";
: 	getline( cin, input );
: 	cout << "The string is: " << input << endl;
: 	return 0;
: }
: 

:

You could but wasn't there a bug in that (or a version of it)? I tried using it for a project only 3 months ago and had to give up and write the getline function myself.

:
: : Or you could just use..
: :

: : #include <string>
: : #include <iostream>
: : using namespace std;
: : 
: : int main(int argc, char* argv[])
: : {
: : 	string input;
: : 	cout << "Enter a string: ";
: : 	getline( cin, input );
: : 	cout << "The string is: " << input << endl;
: : 	return 0;
: : }
: : 

: :
:
: You could but wasn't there a bug in that (or a version of it)? I tried using it for a project only 3 months ago and had to give up and write the getline function myself.

VS 6.0 has the famous getline bug.

Here is the page that shows the fix

http://support.microsoft.com/default.aspx?scid=kb;en-us;240015

Once you make this change getline should work for you.