Hi,

I am having a problem in opening/accessing a file which has a long name, more than 8 characters of length. How can i access a file:
1- with a long name
2- two files with same name(more than 8 characters) having the last charcter different. For example, originalfile1.txt is shown as origin~1.txt and originalfile2.txt is shown as origin~2.txt in dos. How can i read these two files in C++.

I'll be grateful if anyone can help

Thanks in advance!!

This message was edited by stober at 2006-7-13 3:55:1

---

: Hi,
:
: I am having a problem in opening/accessing a file which has a long name, more than 8 characters of length. How can i access a file:
: 1- with a long name
: 2- two files with same name(more than 8 characters) having the last charcter different. For example, originalfile1.txt is shown as origin~1.txt and originalfile2.txt is shown as origin~2.txt in dos. How can i read these two files in C++.
:
: I'll be grateful if anyone can help
:
: Thanks in advance!!
:


What compiler are you using? If you are using 16-bit compiler such as Turbo C then you don't have much choice but to use the 8.3 filenames you posted.

: This message was edited by stober at 2006-7-13 3:55:1

---

: : Hi,
: :
: : I am having a problem in opening/accessing a file which has a long name, more than 8 characters of length. How can i access a file:
: : 1- with a long name
: : 2- two files with same name(more than 8 characters) having the last charcter different. For example, originalfile1.txt is shown as origin~1.txt and originalfile2.txt is shown as origin~2.txt in dos. How can i read these two files in C++.
: :
: : I'll be grateful if anyone can help
: :
: : Thanks in advance!!
: :
:
:
: What compiler are you using? If you are using 16-bit compiler such as Turbo C then you don't have much choice but to use the 8.3 filenames you posted.
:
:
:
Thanks for the reply stober....
It is an Win32 console application in VC++. Is there a solution for the problem?
Thanks in advance

: It is an Win32 console application in VC++. Is there a solution for the problem?


what version of that compiler? I know all VC++ 6.0 and newer compilers support long filenames. VC++ 1.52C is a 16-bit compiler and does not. It was the last 16-bit compiler Microsoft produced.

: : It is an Win32 console application in VC++. Is there a solution for the problem?
:
:
: what version of that compiler? I know all VC++ 6.0 and newer compilers support long filenames. VC++ 1.52C is a 16-bit compiler and does not. It was the last 16-bit compiler Microsoft produced.
:

Its VC++ 6.0. The file with a long name is not being read. Also the one with a space in the name.

: : : It is an Win32 console application in VC++. Is there a solution for the problem?
: :
: :
: : what version of that compiler? I know all VC++ 6.0 and newer compilers support long filenames. VC++ 1.52C is a 16-bit compiler and does not. It was the last 16-bit compiler Microsoft produced.
: :
:
: Its VC++ 6.0. The file with a long name is not being read. Also the one with a space in the name.
:
There shouldn't be any problem reading the file. Post the code, please.


Greets,
Eric Goldstein
http://www.gvh-maatwerk.nl

: : : : It is an Win32 console application in VC++. Is there a solution for the problem?
: : :
: : :
: : : what version of that compiler? I know all VC++ 6.0 and newer compilers support long filenames. VC++ 1.52C is a 16-bit compiler and does not. It was the last 16-bit compiler Microsoft produced.
: : :
: :
: : Its VC++ 6.0. The file with a long name is not being read. Also the one with a space in the name.
: :
: There shouldn't be any problem reading the file. Post the code, please.
:
:
: Greets,
: Eric Goldstein
: http://www.gvh-maatwerk.nl
:
:
:
Here's the relevant code:

ifstream ifile;

setpath(argv[1]);//change the working dir

if(get_cdr_structure(format,values))//read the file structure
{
printlabel();

//open the cdr
ifile.open(argv[2]);
if (ifile)
{
//my code
}

}

The code works well if argv[2] contains a short path and a short name
Thanks in advance

: : : : : It is an Win32 console application in VC++. Is there a solution for the problem?
: : : :
: : : :
: : : : what version of that compiler? I know all VC++ 6.0 and newer compilers support long filenames. VC++ 1.52C is a 16-bit compiler and does not. It was the last 16-bit compiler Microsoft produced.
: : : :
: : :
: : : Its VC++ 6.0. The file with a long name is not being read. Also the one with a space in the name.
: : :
: : There shouldn't be any problem reading the file. Post the code, please.
: :
: :
: : Greets,
: : Eric Goldstein
: : http://www.gvh-maatwerk.nl
: :
: :
: :
: Here's the relevant code:
:
: ifstream ifile;
:
: setpath(argv[1]);//change the working dir
:
: if(get_cdr_structure(format,values))//read the file structure
: {
: printlabel();
:
: //open the cdr
: ifile.open(argv[2]);
: if (ifile)
: {
: //my code
: }
:
: }
:
: The code works well if argv[2] contains a short path and a short name
: Thanks in advance

Aha. Since the file is passed through an argument nd contains spaces, the runtime splits the filename in two or more arguments.
You can verify that by inspecting argv[3]. You'll see that it contains the rest of the filename.
Try passing the filename within double quotes.



Greets,
Eric Goldstein
http://www.gvh-maatwerk.nl

: Aha. Since the file is passed through an argument nd contains spaces, the runtime splits the filename in two or more arguments.
: You can verify that by inspecting argv[3]. You'll see that it contains the rest of the filename.
: Try passing the filename within double quotes.
:


you can probably fix this problem by quoting the path on the command line

c:>myprogram.exe "an argument with spaces must be quoted here" <Enter>

: : Aha. Since the file is passed through an argument nd contains spaces, the runtime splits the filename in two or more arguments.
: : You can verify that by inspecting argv[3]. You'll see that it contains the rest of the filename.
: : Try passing the filename within double quotes.
: :
:
:
: you can probably fix this problem by quoting the path on the command line
:

: c:>myprogram.exe "an argument with spaces must be quoted here" <Enter>
: 

:

Thanks stober and tsagld, my problem is solved. I have added the following lines:

strcpy(cdrpath,argv[2]);
if(argc>3)
for(int i=3;i<argc;i++)
{
strcat(cdrpath," ");
strcat(cdrpath,argv[i]);
}
my code is working well with all sorts of filepaths and filenames.
Thankyou!!!!!

This message was edited by tsagld at 2006-7-24 23:37:41

---

: : : Aha. Since the file is passed through an argument nd contains spaces, the runtime splits the filename in two or more arguments.
: : : You can verify that by inspecting argv[3]. You'll see that it contains the rest of the filename.
: : : Try passing the filename within double quotes.
: : :
: :
: :
: : you can probably fix this problem by quoting the path on the command line
: :

: : c:>myprogram.exe "an argument with spaces must be quoted here" <Enter>
: : 

: :
:
: Thanks stober and tsagld, my problem is solved. I have added the following lines:

 
: strcpy(cdrpath,argv[2]);
: 	if(argc>3) this line is not really necessary
: 		for(int i=3;i<argc;i++)
: 		{
: 			strcat(cdrpath," ");
: 			strcat(cdrpath,argv[i]);
: 		}

: my code is working well with all sorts of filepaths and filenames.
: Thankyou!!!!!

Realize that your code only works if the path is the last argument in the list. Besides that, you have to allocate space for cdrpath before you know how much space is needed. That's vulnerable to buffer overflows.
As I stated before, it is better to pass the path between double quotes. Stober gave an example.


Greets,
Eric Goldstein
http://www.gvh-maatwerk.nl