Write a program that allows a user to enter two integer values. Display every whole number that falls between these values.

2. Write a program for a furniture company. Ask the user to choose P for pine, O for oak or M for mahogany. Show the price of a table manufactured with the chosen wood. Prices for pine tables are $100, oak tables are $225 and mahogany tables are $350.

Not sure if you still need this. Here's problem 1.

#include <iostream>

using namespace std;

int main ()
{
    cout << "Enter two values" << endl;
    int a,b;
    cin >> a >> b;
    
    cout << "\n\n\n\n";
    while(a<b){
        cout << a << ", "; //prints number; comma for formatting
        a++; /*raises the value of "a" until it is one less than b, ending the
        loop.*/ 
        }
        cout << b; /* The while loop iterated until one less than b.  We still
        wish to print b. Prints only number with no comma after it*/
        
    int z;
    cin >> z;
    return 0;
    
}

Not sure if you still need this. Here's problem 1.

#include <iostream>

using namespace std;

int main ()
{
    cout << "Enter two values" << endl;
    int a,b;
    cin >> a >> b;
    
    cout << "\n\n\n\n";
    while(a<b){
        cout << a << ", "; //prints number; comma for formatting
        a++; /*raises the value of "a" until it is one less than b, ending the
        loop.*/ 
        }
        cout << b; /* The while loop iterated until one less than b.  We still
        wish to print b. Prints only number with no comma after it*/
        
    int z;
    cin >> z;
    return 0;
    
}

# include <itream.h>

int main ()

{

int a,b,c;

cout << "enter you values"<<endl;
cin <<a<<b;

Do
{
a= a+1
count <<a<<endl;
a= a+1

}
(while a!=b)


return 0;
}


//this will display all the unit_values between a and b.

***disregard my last post. This code will work correctly in both cases a<b & a>b [and if a=b it it goes into an infinate loop]***

include <iostream>


int main()
{
int a,b;

cout<< "Enter your values."<<endl;
cin>>a>>b;


if (a<b)
do
{
a=a+1;
cout <<a<< endl;
}
while(a!=b);

else

do
{
a=a-1;
cout <<a<< endl;
}
while(a!=b);

return 0;
}

# include <itream.h>

int main ()

{

int a,b,c;

cout << "enter you values"<<endl;
cin <<a<<b;

Do
{
a= a+1
count <<a<<endl;
a= a+1

}
(while a!=b)


return 0;
}


//this will display all the unit_values between a and b.

***Also, I'm trying this approach as a resolve for your question. But I thik its a more appropriate approach to be used for this question***

#include <iostream>

using namespace std;

int main()
{
int a,b,c;
double r;
char ch,o,m,p;

c=0;

cout<< "Enter your spending limit."<<endl;
cin>>b;
cout<< "Please choose between Pine, Oak, Mahoganhi."<<endl;
cin>>ch;

switch(ch)
{



case 'p':

a = 100;
do
{
r=c+a;
cout<<r<<endl;
c=r;
}
while(r!=b);
break;

case 'o':
a=225;

do
{
r=c+a;
cout<<r<<endl;
c=r;
}
while(r!=b);
break;

case 'm':

a=350;
do
{
r=c+a;
cout<<r<<endl;
c=r;
}
while(r!=b);
break;
}


return 0;
}