How do i get the program to ask the user to input the numbers, and then ask the user to input the operator.
 
Instead of just having the user inputting only the operators.

/*
 * Created by Opticknerve
 * User: Administrator
 * Date: 5/20/2009
 * Time: 8:59 AM
 * 
 */

using System;
class Maths
{
	public static void Main()
	{
		Maths m = new Maths();
		m.ShowDemo();
	}
	void ShowDemo()
	{
	
		int Addition = 0;
		int Subtraction = 0;
		int Multiplication = 0;
		int Devision = 0;
		
		int num1 = 60;
		int num2 = 50;
		
		Addition = num1 + num2;
		Subtraction = num1 - num2;
		Multiplication = num1 * num2;
		Devision = num1/num2;
		
		Console.WriteLine("PLease choose any of the following operators +,-,*,/");
		string Sign = Console.ReadLine();
		switch (Sign)
		{
			case "+":	
				Console.WriteLine("You have chosen the + operator");
				Console.WriteLine("Number 1 + Number 2 = :" + Addition);
				break;
			case "-":
				Console.WriteLine("You have chosen the - operator");
				Console.WriteLine("Number 1 - Number 2 = :" + (Subtraction));
				break;
			case "*":
				Console.WriteLine("You have chosen the * operator");
				Console.WriteLine("Number 1 * Number 2 = :" + (Multiplication));
				break;
			case "/":
				Console.WriteLine("You have chosen the / operator");
				Console.WriteLine("Number 1 / Number 2 = :" + (Devision));
				break;
			default:
			Console.WriteLine("Please Choose an operator");
			break;
		}
	}
}

Thanx Psightoplazm for your help.

sticking strictly to your example you would want to add a new method to your class:

private double DoMath(int val1, int val2, string oper)
{
    switch (oper)
    {
        case "+":	
            return (val1 + val2);
        case "-":
            return (val1 - val2);
        case "*":
            return (val1 * val2);
        case "/":
            return (val1 / val2);
    }
    return 0;
}

Then in your main code you will want to ask the user for the additional input:

now here is the easiest method to understand:

using System;
class Maths
{
    public static void Main()
    {
        Maths m = new Maths();
        m.ShowDemo();
    }
    void ShowDemo()
    {
        Console.Write("Please enter the first value:");
        var num1 = int.Parse(Console.ReadLine());
        Console.Write("Please enter the second value:");
        var num2 = int.Parse(Console.ReadLine());
        Console.Write("Please enter the desired function (+,-,*,/)");
        var oper= Console.ReadLine();
        var result = DoMath(num1, num2, oper);

        Console.WriteLine("The result to your equation is: " + result);
    }

    private double DoMath(int val1, int val2, string oper)
    {
        switch (oper)
        {
            case "+":	
                return (val1 + val2);
            case "-":
                return (val1 - val2);
            case "*":
                return (val1 * val2);
            case "/":
                return (val1 / val2);
        }
        return 0;
    }
}

However if you wanted to make this a little easier for the user you might want to use a regular expression to parse a plain text expression:

Console.WriteLine("Please enter your equation:");
var equation = Console.ReadLine();
var data = Regex.Match(equation, "(?<val1>\\d+)\\s*(?<sign>[+\\-*/])\\s*(?<val2>\\d+)");
var val1 = int.Parse(data.Groups["val1"].Value);
var val2 = int.Parse(data.Groups["val2"].Value);
var operator = data.Groups["sign"].Value;
var result = DoMath(val1, val2, operator);
Console.WriteLine("Your answer is " + result);

To explain some of the stuff in there -
int.Parse - is a way of converting a 'string' to an 'int'
A regular expression matches a string to a pattern and allows you to pull information from it - please see this page for more info
></\/~Psightoplasm`~

Hey thanx psightoplazm. The regular expressions are very complex at he moment but i think with time and dedication, i will get a hang of them thanx alot for your help.

Hey thanx psightoplazm. The regular expressions are very complex at he moment but i think with time and dedication, i will get a hang of them thanx alot for your help.