Can anyone help me in solving the derivative of the equation f=sinh(πx)*cos(πy)/sinh(π)? I need to derive it based on its unit normal vector, means i need the answer of df/dn.

[π =pi=3.142]

Thanks.

i may be wrong, but you just take the derivative of f. that means, if you have F=A/B then F' = [B *(derivative of A)]-[A * (derivative of B)] / B^2

in other words: low D high minus high D low all over low squared.
where D means derivative of.

Are you searching a numerical solution or a symbolic one?

I'm trying to solve it analytically, not numerically.

Thanks for your reply. But unfortunately, you have misunderstood my question.
I know derivative of a funtion, but this equation, it doesn't have the unit normal vector,n in it, so I don't know how to derive it become df/dn. The way you teach me is to derive the equation become df/dx or df/dy.

By the way, thanks for your reply.

To whom it may concern,
I had already solved the problem. So, need not to think for me on this derivative problem. Thanks.

Can you tell me how did you solve the problem?

Ok, please refer to the attachment. Hope you can understand what did I write there. :)

Thank you.