Hello,

I have string like this:

...ab...abc.....def

the dots are spaces. How can I count from start of string to the end of first set of chars that are not spaces.

Thanks
Bob

: Hello,
:
: I have string like this:
:
:

: ...ab...abc.....def
: 

:
: the dots are spaces. How can I count from start of string to the end of first set of chars that are not spaces.
:
: Thanks
: Bob
:
Here is part of a small code, which should help you on your way:

  for i := 1 to Length(s) do
    if s[i] <> ' ' then // Check if i-th character isn't a space
    begin
      {Do Something}
    end;

: : Hello,
: :
: : I have string like this:
: :
: :

: : ...ab...abc.....def
: : 

: :
: : the dots are spaces. How can I count from start of string to the end of first set of chars that are not spaces.
: :
: : Thanks
: : Bob
: :
: Here is part of a small code, which should help you on your way:
:

:   for i := 1 to Length(s) do
:     if s[i] <> ' ' then // Check if i-th character isn't a space
:     begin
:       {Do Something}
:     end;
: 

:

Hello....thanks for reply. I can get index of spaces and even the ab chars. I just can't copy the ' ab' then delete from string and do over to get the rest. Sorry for stupid.

Bob

: : : Hello,
: : :
: : : I have string like this:
: : :
: : :

: : : ...ab...abc.....def
: : : 

: : :
: : : the dots are spaces. How can I count from start of string to the end of first set of chars that are not spaces.
: : :
: : : Thanks
: : : Bob
: : :
: : Here is part of a small code, which should help you on your way:
: :

: :   for i := 1 to Length(s) do
: :     if s[i] <> ' ' then // Check if i-th character isn't a space
: :     begin
: :       {Do Something}
: :     end;
: : 

: :
:
: Hello....thanks for reply. I can get index of spaces and even the ab chars. I just can't copy the ' ab' then delete from string and do over to get the rest. Sorry for stupid.
:
: Bob
:
:
Then I suggest a nested while-do loop:

  while s <> '' do
  begin
    Part := '';
    while s[1] = ' ' do // Move all the spaces into part
    begin
      Part := Part + s[1];
      Delete(s, 1, 1);
    end;
    while s[1] <> ' ' do // Move all the letters into part
    begin
      Part := Part + s[1];
      Delete(s, 1, 1);
    end;
    // Now part contains the left-most spaces and letters from s
  end;

This code looks complex, but it is quite easy to follow in the debugger. I would suggest that you look at what happens to s and Part while stepping through the code.

: Then I suggest a nested while-do loop:
:

:   while s <> '' do
:   begin
:     Part := '';
:     while s[1] = ' ' do // Move all the spaces into part
:     begin
:       Part := Part + s[1];
:       Delete(s, 1, 1);
:     end;
:     while s[1] <> ' ' do // Move all the letters into part
:     begin
:       Part := Part + s[1];
:       Delete(s, 1, 1);
:     end;
:     // Now part contains the left-most spaces and letters from s
:   end;
: 

: This code looks complex, but it is quite easy to follow in the debugger. I would suggest that you look at what happens to s and Part while stepping through the code.
:

OK....yes I see how it works. Nice. How to stop loop when s=''. Get access violation when string is empty. Seems the inside(?) loop looking for ' ' but finds '' and crash. Maybe boolean?

Bob

: : Then I suggest a nested while-do loop:
: :

: :   while s <> '' do
: :   begin
: :     Part := '';
: :     while s[1] = ' ' do // Move all the spaces into part
: :     begin
: :       Part := Part + s[1];
: :       Delete(s, 1, 1);
: :     end;
: :     while s[1] <> ' ' do // Move all the letters into part
: :     begin
: :       Part := Part + s[1];
: :       Delete(s, 1, 1);
: :     end;
: :     // Now part contains the left-most spaces and letters from s
: :   end;
: : 

: : This code looks complex, but it is quite easy to follow in the debugger. I would suggest that you look at what happens to s and Part while stepping through the code.
: :
:
: OK....yes I see how it works. Nice. How to stop loop when s=''. Get access violation when string is empty. Seems the inside(?) loop looking for ' ' but finds '' and crash. Maybe boolean?
:
: Bob
:
:
Yes, after the Delete() check if the string is empty and call Break() to get out of the loop.

: : : Then I suggest a nested while-do loop:
: : :

: : :   while s <> '' do
: : :   begin
: : :     Part := '';
: : :     while s[1] = ' ' do // Move all the spaces into part
: : :     begin
: : :       Part := Part + s[1];
: : :       Delete(s, 1, 1);
: : :     end;
: : :     while s[1] <> ' ' do // Move all the letters into part
: : :     begin
: : :       Part := Part + s[1];
: : :       Delete(s, 1, 1);
: : :     end;
: : :     // Now part contains the left-most spaces and letters from s
: : :   end;
: : : 

: : : This code looks complex, but it is quite easy to follow in the debugger. I would suggest that you look at what happens to s and Part while stepping through the code.
: : :
: :
: : OK....yes I see how it works. Nice. How to stop loop when s=''. Get access violation when string is empty. Seems the inside(?) loop looking for ' ' but finds '' and crash. Maybe boolean?
: :
: : Bob
: :
: :
: Yes, after the Delete() check if the string is empty and call Break() to get out of the loop.
:
Yes, Break that is it. Thank you much. You are big help. One more question. Is this consider inner and outer loop? Sorry, just learning.

Bob

: : : : Then I suggest a nested while-do loop:
: : : :

: : : :   while s <> '' do
: : : :   begin
: : : :     Part := '';
: : : :     while s[1] = ' ' do // Move all the spaces into part
: : : :     begin
: : : :       Part := Part + s[1];
: : : :       Delete(s, 1, 1);
: : : :     end;
: : : :     while s[1] <> ' ' do // Move all the letters into part
: : : :     begin
: : : :       Part := Part + s[1];
: : : :       Delete(s, 1, 1);
: : : :     end;
: : : :     // Now part contains the left-most spaces and letters from s
: : : :   end;
: : : : 

: : : : This code looks complex, but it is quite easy to follow in the debugger. I would suggest that you look at what happens to s and Part while stepping through the code.
: : : :
: : :
: : : OK....yes I see how it works. Nice. How to stop loop when s=''. Get access violation when string is empty. Seems the inside(?) loop looking for ' ' but finds '' and crash. Maybe boolean?
: : :
: : : Bob
: : :
: : :
: : Yes, after the Delete() check if the string is empty and call Break() to get out of the loop.
: :
: Yes, Break that is it. Thank you much. You are big help. One more question. Is this consider inner and outer loop? Sorry, just learning.
:
: Bob
:
The 2 blue loops are considered to be inner loops, while the black loop is the outer loop. In case of 3+ nested loops, 1 or more loop(s) can be considered to be both.