This message was edited by the gautam at 2002-4-12 4:20:53
This message was edited by the gautam at 2002-4-12 4:18:58
I am not sure but I think it will be in the following way
BITMAPFILEHEADER bf;
BITMAPINFOHEADER bi;
// open the file in binary mode
....
// read in the file header info
fread(&bf, 1, sizeof(BITMAPFILEHEADER), fp);
// do the test and etc to check if its a bitmap
....
// read in the info header - if you are looking for portability then
// you shouldn't trust the sizeof and you should calculate the sizes
// of structure beforehand
fread(&bi, 1, sizeof(BITMAPINFOHEADER), fp);
....
// check for monochrome - bitcount = 1
....
// if bitcount <= 8 then we have a color table, so we need to read in the color table.
......
// if we have pixel imformation - we read that in to an array
.....
// close the file
.....
You should look at the bitmap file format for more information. Also note that the bitmap is generally saved upside down - so you might have to flip it.
: I am presently working on a project that requires all the image data of a monochrome bitmap file be stored in a array. I have no idea how to do this.
:
: This is my present code which spits out garbage:
:
: '''''
: FILE *filePointer2;
:
: filePointer2 = fopen(temp2,"rb"); //temp2 holds the present filename
: //there is 1000 .bmp files to be
: //opened and read, this has been
: //successfully completed my only
: //problem is reading in the "raw
: //data" of each bitmap file
:
: fgets(tempHolder2,200,filePointer2);
: cout << tempHolder2;
:
: ''''
:
: I'm using MS Visual C++ 6.0. Any advice/help would be great! Please note this idea of reading data from a image file is completely new to me; I have no experience. Thanks in advance!
:
: stuckatone@yahoo.com
:
