I am trying to split a string containing "filename.wav"

I tried the following

String[]stringArray = fileString.split(".")

and also

String[]stringArray = fileString.split("\.")

Somehow I can't get JAVA to split it on the "." symbol because it is a reserved character in regular exressions. I read the page on regular expressions and couldn't find a way for it to recognize this character. I even tried it in octal and hex format...

Help!!

: I am trying to split a string containing "filename.wav"
:
: I tried the following
:
: String[]stringArray = fileString.split(".")
:
: and also
:
: String[]stringArray = fileString.split("\.")
:
: Somehow I can't get JAVA to split it on the "." symbol because it is
: a reserved character in regular exressions. I read the page on
: regular expressions and couldn't find a way for it to recognize this
: character. I even tried it in octal and hex format...
:
: Help!!
:
:
:
I've had a similar problem, and solved it using the regex character-selection group: []. Example:

  split("[.]");

: I tried the following
:
: String[]stringArray = fileString.split(".")
:
: and also
:
: String[]stringArray = fileString.split("\.")
Thing is, I think Java itself is getting the \ and saying "ah, but there's nothing to escape with a ., so I just leave a literal . there". What you need, is for the \ to be passed along to the regex engine, so try escaping that.

String[]stringArray = fileString.split("\\.")

Jonathan

###
for(74,117,115,116){$::a.=chr};(($_.='qwertyui')&&
(tr/yuiqwert/her anot/))for($::b);for($::c){$_.=$^X;
/(p.{2}l)/;$_=$1}$::b=~/(..)$/;print("$::a$::b $::c hack$1.");