I am trying to make simple malware removal, but I dont know how to get the percentage of path that I want to scan. For example I scan c:\folder, I want to get the percentage to make progress bar while scanning.

Thx a lot.

Let be m the total number of files in a folder, n the current file you process (a nonzero number) then current percentage (cp) would be: cp:=n*100/m

How can I get m ? Do I have to scan twice? :(

: How can I get m ? Do I have to scan twice? :(

No, you have to use the findfirst and findnext procedures from the Dos unit to get all the filenames in a folder first. That gives you the m. When you scan you'll have to open each file for scan, starting from 1 (n).

If I use findfirst or findnext, that will wasting time???

: If I use findfirst or findnext, that will wasting time???

No time wasting there (takes only a fraction of a second), beside that's the only way to find out the file names from a folder...unless you read the FAT directly and process the info but that's a bit beyond plain Pascal's capability, you'd have to rely on assembly there...