Hey Jonathan !
Hmmm you could be right what comes before this is this ..
$op = $_SESSION['operator'];
echo ($op);
$res = mysql_query("select * from online_users WHERE ACTIVE='Y' and userid='$op' and (now()-ts) < 240");
//$res = mysql_query("select * from online_users WHERE ACTIVE='Y' and userid='$op' ");
$i = 1;
while ($row = mysql_fetch_array($res))
thing is everything is set up table wise in the DB ....
: :
http://www.helplive.net/phponline/test5.php is the URL:
: :
: :
: :
: : Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/content/h/e/l/helplive/html/phponline/test5.php on line 55
: :
: :
Hey Jonathan -
hmmmm that might be it ....I mean
: : anyone know ?
: :
: Probably because whatever you're passing to mysql_fetch_array came from an attempt to execute an invalid query. The problem may well be prior to this line.
:
: Jonathan
:
: ###
: for(74,117,115,116){$::a.=chr};(($_.='qwertyui')&&
: (tr/yuiqwert/her anot/))for($::b);for($::c){$_.=$^X;
: /(p.{2}l)/;$_=$1}$::b=~/(..)$/;print("$::a$::b $::c hack$1.");
:
:
