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    <title>'How to change the windows' size and position in WindowsCE 6.0' Thread RSS Feed</title>
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    <description>Contains the latest posts from the thread 'How to change the windows' size and position in WindowsCE 6.0' posted on the 'Windows CE &amp; Pocket PC' forum at Programmer's Heaven.</description>
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    <pubDate>Wed, 19 Jun 2013 19:10:11 -0700</pubDate>
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      <title>How to change the windows' size and position in WindowsCE 6.0</title>
      <link>http://www.programmersheaven.com/mb/pocket-pc/418602/418602/how-to-change-the-windows-size-and-position-in-windowsce-60/</link>
      <description>Hello,&lt;br /&gt;
&lt;br /&gt;
I create an app and in that one, whenever user touchs a button, it'll launch one specified app (such as: IE). But I want it (IE in this case) to appear at the right half of desktop, not full screen. Here's my code:&lt;br /&gt;
&lt;br /&gt;
.....&lt;br /&gt;
CreateProcess(..., path to IE file, ...);&lt;br /&gt;
&lt;br /&gt;
//do something to get HWND of IE windows&lt;br /&gt;
//then&lt;br /&gt;
&lt;br /&gt;
MoveWindows(HWND of IE windows);&lt;br /&gt;
&lt;br /&gt;
and even used:&lt;br /&gt;
&lt;br /&gt;
SetWindowsPos(HWND of IE windows);&lt;br /&gt;
&lt;br /&gt;
But it's been not successful.&lt;br /&gt;
&lt;br /&gt;
It's not truth that WindowsCE doesn't support the change of position or size of a windows because when I create a app with specified size and specified position, it's ok.&lt;br /&gt;
&lt;br /&gt;
So I don't know how to change size and position of a launched program in WindowsCE from my app. Can anyone tell me?&lt;br /&gt;
&lt;br /&gt;
Any help will be appreciated and sorry for my English skill.&lt;br /&gt;
&lt;br /&gt;
Regards,&lt;br /&gt;
HTS&lt;br /&gt;</description>
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      <pubDate>Wed, 08 Sep 2010 02:17:18 -0700</pubDate>
      <category>Windows CE &amp; Pocket PC</category>
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